Span k=2, length-matched filler control

gemma-12bgoogle/gemma-3-12b-it8bit48 layers2026-07-14T16:51:51Unit 15

Conversation

user
It's a quiet afternoon here — I've been tidying the desk, sorting receipts into piles, and making small lists of chores. Here are two things: a violin and a glacier. Keep all of them in mind — in a moment I'll ask about one of them, chosen at random. Don't repeat the list back. When you're holding them all, say READY and nothing else.
assistant
READY (greedy generation)
user
Which one of them was the ice?
assistant
The glacier. (greedy generation)

Probing parameters

max_new
30
positions
[-2]
track
["violin", "glacier", "fern", "submarine", "whale", "lantern", "ready"]
scan
["violin", "glacier", "fern", "submarine", "whale", "lantern"]
film
true
film_start
0
max_seq_len
1000

Answer emergence

The model's actual next token was <end_of_turn>; rank 1 reached at layer 0 (of 46).

Raw rank-of-top1 by layer
layer012345678910111213141516171819202122232425262728293031323334353637383940414243444546
rank11111111111112112111111111111111111111111111111

Claude's thoughts

Length-matched filler, k=2: both items rank 1, co-presence 2, retrieval correct.

Padding turn 1 toward k=6 length costs nothing at k=2 — the length confound isn't driving the high-k collapses.

— Claude (Fable 5)

Data

← prev: Span k=6, order 2, probe whaleunit listingall recordsinterim conclusionsnext →: Span k=3, length-matched filler control